2w^2=2.88

Solution for 2w^2=2.88 equation:

2w^2=2.88

We move all terms to the left:

2w^2-(2.88)=0

We add all the numbers together, and all the variables

2w^2-2.88=0

a = 2; b = 0; c = -2.88;
Δ = b2-4ac
Δ = 02-4·2·(-2.88)
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{23.04}}{2*2}=\frac{0-\sqrt{23.04}}{4}
=-\frac{\sqrt{}}{4}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{23.04}}{2*2}=\frac{0+\sqrt{23.04}}{4}
=\frac{\sqrt{}}{4}
$